Question 855203: tim has $3.45 in dimes and quarters. there are three more dimes than quarters. how many of each coin does he have? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! tim has $3.45 in dimes and quarters. there are three more dimes than quarters. how many of each coin does he have?
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The hard way:
d = q + 3
10d + 25q = 345
10(q+3) +25q = 345
35q = 315
q = 9
d = 12
--> 9 quarters & 12 dimes
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The easy way:
He has p pairs of quarters & dimes + 3 dimes = 345
p pairs of quarters & dimes = 315
315/35 = 9 pairs
--> 9 quarters & 12 dimes
