SOLUTION: I need to solve the equation{{{4^(3x)=7^(x+1)}}}.My teacher uses handouts to teach,so I am stumped with no material to reference.Please help.Thanks.
Question 85515: I need to solve the equation.My teacher uses handouts to teach,so I am stumped with no material to reference.Please help.Thanks. Found 2 solutions by stanbon, jim_thompson5910:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 4^(3x)=7^(x+1)
Since the variables are in the exponent, take the log of both sides to get:
(3x)log4 = (x+1)log7
(3log4)x = (log7)x + log7
(3log4-log7)x = log7
log[(4^3)/7]x = log7
0.961081934x = 0.84509804
x=0.8793194525...
===========
Cheers,
Stan H.