SOLUTION: I am trying to figure this out and keep running into a road block.
Multiply.
3xy^3*2x^2y*4xy^2=
This is as far as I have gotten and not sure that I am correct so far.
7xy^5*2
Algebra ->
Linear-equations
-> SOLUTION: I am trying to figure this out and keep running into a road block.
Multiply.
3xy^3*2x^2y*4xy^2=
This is as far as I have gotten and not sure that I am correct so far.
7xy^5*2
Log On
Question 8551: I am trying to figure this out and keep running into a road block.
Multiply.
3xy^3*2x^2y*4xy^2=
This is as far as I have gotten and not sure that I am correct so far.
7xy^5*2x^2y=This doesn't look like I am on the right track for some reason. Answer by rapaljer(4671) (Show Source):
Now, multiply the base numbers 3*2*4, which is 24.
Add the exponents of x, which are 1 +2+1, for a total of 4.
Add the exponents of y, which are 3+1+2, for a total of 6.