SOLUTION: Log5 (y+ 1) - log5 8 = log5 (y- 3) - log5 6

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Question 854913: Log5 (y+ 1) - log5 8 = log5 (y- 3) - log5 6
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi,

Log5 (y+ 1) - log5 8 = log5 (y- 3) - log5 6

Log5 (y+ 1) - log5 8 - log5 (y- 3) + log5 6 = 0

Log5 6(y+ 1)/8(y-3)= 0

   6%28y%2B+1%29%2F8%28y-3%29=+1

    6y + 6 = 8y - 24

         30 = 2y

         15 = y