SOLUTION: If an investment is $9500, part of it at 11% and part of it at 8%. For a certain year the total is $937. How much was invested at each rate?

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Question 854903:
If an investment is $9500, part of it at 11% and part of it at 8%. For a certain year the total is $937. How much was invested at each rate?
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
.11x+.08(9500-x)=937
.11x+760-.08x=937
.03x=937-760
.03x=177
x=177/.03
x=$5,900 invested @ 11%
9,500-5,900=$3,600 invested @ 8%
Proof:
.11*5,900+.08*3,600=937
649+288=937
937=937