SOLUTION: PLEASE HELP ME! a cable hangs between two poles that are 24 feet apart. The height of the cable (in feet) is given by the equation. h(x)=12(e^0.02x + e^-0.02x) where -1

Algebra ->  Test -> SOLUTION: PLEASE HELP ME! a cable hangs between two poles that are 24 feet apart. The height of the cable (in feet) is given by the equation. h(x)=12(e^0.02x + e^-0.02x) where -1      Log On


   

Question 854902: PLEASE HELP ME!
a cable hangs between two poles that are 24 feet apart. The height of the cable (in feet) is given by the equation.

h(x)=12(e^0.02x + e^-0.02x)
where -12< x<12 and x is the horizontal position (in feet).
Question: Find the height of the cable at either pole.
PLEASE SHOW ME ON WHAT DID YOU PUT ON YOUR CALCULATOR! SO I CAN UNDERSTAND IT.
THANKS!
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
h%28-12%29=12%28e%5E%280.02%2812%29%29%2Be%5E%28-0.02%2812%29%29%29
h%28-12%29=12%28e%5E%280.24%29%2Be%5E%28-0.24%29%29
On my desktop calculator, its INV LN, since e%5Ex and ln%28x%29 are inverses of each other.
In EXCEL, it's =EXP(0.24)+EXP(-0.24).
h%28-12%29=h%2812%29=12%281.271%2B0.7866%29
h%28-12%29=24.69%29 feet