SOLUTION: Please help me the question is if sin theta= (2 sqrt5)/5 and cos theta=(-sqrt5)/5 what quadrant would the theta be in.
For sin I have found that y=2 and r= sqrt5
For cos I have
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-> SOLUTION: Please help me the question is if sin theta= (2 sqrt5)/5 and cos theta=(-sqrt5)/5 what quadrant would the theta be in.
For sin I have found that y=2 and r= sqrt5
For cos I have
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Question 854565: Please help me the question is if sin theta= (2 sqrt5)/5 and cos theta=(-sqrt5)/5 what quadrant would the theta be in.
For sin I have found that y=2 and r= sqrt5
For cos I have found that x= -sqrt5 and r= 5
How would this problem work if the r's arent the same
You can put this solution on YOUR website! The answer to your question (r's are the same) is that they are the same! The difference is that you defined y = 2 for the sin function, but it is really y = 2 sqrt(5). Then the r for the sin is r = (sqrt5)*(sqrt5) or r = 5. In fact, the value of r must be the same!
The angle theta is in the second quadrant.
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