SOLUTION: a minor league baseball team plays 77 games in a season. If the team won 17 more than twice as many games as they lost, how many wins and losses did the team have

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Question 854508: a minor league baseball team plays 77 games in a season. If the team won 17 more than twice as many games as they lost, how many wins and losses did the team have

Found 2 solutions by lwsshak3, josmiceli:
Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website!
a minor league baseball team plays 77 games in a season. If the team won 17 more than twice as many games as they lost, how many wins and losses did the team have
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let x=number of games lost
2x+17=number of games won
x+(2x+17)=77
3x+17=77
3x=60
x=20
2x+17=57
number of games lost=20
number of games won=57

Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
Let = number of games they won
Let = number of games they lost
------------------------------------
(1)
(2)
-------------------
substitute (2) into (1)
(1)
(1)
(1)
(1)
and, since
(1)
(1)
(1)
There were 20 losses and 57 wins
check:
(2)
(2)
(2)
(2)
OK