SOLUTION: Please factorize the following 15x2 -2x -1 and a3 +6a2b +12ab3 +8b3 thank you

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Question 854423: Please factorize the following
15x2 -2x -1
and
a3 +6a2b +12ab3 +8b3
thank you

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
15x%5E2+-2x+-1=%283x-1%29%285x%2B1%29

a%5E3+%2B6a%5E2b+%2B12ab%5E2+%2B8b%5E3=%28a%2B2b%29%5E3
(I know you wrote a%5E3+%2B6a%5E2b+%2B12ab%5E3+%2B8b%5E3 , but I think there was a typo somewhere).

How did I get it?

The factorization of
15x%5E2+-2x+-1=%283x-1%29%285x%2B1%29
is easier to calculate this way:
If y=1%2Fx<-->x=1%2Fy ,


If that is Greek to you, there is another, more traditional way.
To factorize something like 15x%5E2+-2x+-1 , you multiply the coefficients at the ends
(in this case, 15 and -1, that multiply to give -15),
and look for pairs of factors of that result that will add to the middle coefficient (-2 in this case).
When you figure out that 3 and -5 are those factors,
you re-write the polynomial with two middle terms with those coefficients,
that is 3x and -5x in place of the middle term -2x ,
and then you factorize by grouping:


With a%5E3+%2B6a%5E2b+%2B12ab%5E2+%2B8b%5E3 it is a question of realizing that
a%5E3 is the cube of a and
8b%5E3 is the cube of 2b .
That should make you suspect that it could be the cube of a binomial:
%28a%2B2b%29%5E3=a%5E3%2B3%2Aa%5E2%2A%282b%29%2B3%2Aa%2A%282b%29%5E2%2Bb%5E3
If you do the indicated operations,
3%2Aa%5E2%2A%282b%29=6a%5E2b and 3%2Aa%2A%282b%29%5E2=3%2Aa%2A%284b%5E2%29=12ab%5E2 ,
and you find that indeed %28a%2B2b%29%5E3=a%5E3+%2B6a%5E2b+%2B12ab%5E2+%2B8b%5E3