Question 854346: If I am traveling at 90 mph and a car is a quarter mile behind me, how fast must that car (mph) go to catch me within a quarter mile? Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! I will travel .25 miles at 90 mph
Other car will travel .50 miles at 90+y mph
90x=.25,
(90+y)*x=.50
x = 1/360, y = 90
The second car must go 180 mph for 60*1/360=1/6 minute= 10 seconds
