SOLUTION: Identify the center of the conic section whose equation is x 2 + y 2 + 6 x - 4 y - 12 = 0.

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Question 853832: Identify the center of the conic section whose equation is x 2 + y 2 + 6 x - 4 y - 12 = 0.
Answer by lwsshak3(11628) About Me  (Show Source):
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Identify the center of the conic section whose equation is
x 2 + y 2 + 6 x - 4 y - 12 = 0.
x^2+6x+y^2-4y-12=0
complete the square:
(x^2+6x+9)+(y^2-4y+4)=12+9+4
(x+3)^2+(y-2)^2=25
This is an equation of a circle with center at (-3,2) and radius of 5