SOLUTION: The perimeter of a lot is 190 meters. The width is one-fouth the length. Find the dimensions.
This is what I'm doing:
W=1/4L
2L+2W=190
2L+2(1/4L)=190
2L+1/2L=190
2 1/2L=1
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-> SOLUTION: The perimeter of a lot is 190 meters. The width is one-fouth the length. Find the dimensions.
This is what I'm doing:
W=1/4L
2L+2W=190
2L+2(1/4L)=190
2L+1/2L=190
2 1/2L=1
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Question 853578: The perimeter of a lot is 190 meters. The width is one-fouth the length. Find the dimensions.
This is what I'm doing:
W=1/4L
2L+2W=190
2L+2(1/4L)=190
2L+1/2L=190
2 1/2L=190
L= 47 1/2
I looked at my answer key and it says the dimensions are L=76 and W=19. What did I do wrong?
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