SOLUTION: In a certain town, 40% of the eligible voters prefer candidate A, 35% prefer candidate B, and the remaining 25% have no preference. You randomly sample 12 eligible voters. What is

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Question 853352: In a certain town, 40% of the eligible voters prefer candidate A, 35% prefer candidate B, and the remaining 25% have no preference. You randomly sample 12 eligible voters. What is the probability that 7 will prefer candidate A, 2 will prefer candidate B, and the remaining 3 will have no preference?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Using TI: (The syntax is binompdf(n, p, x-value)for singular probability

n = 12, p = .40, p = .35  0r   p = .25

P(x=7) = binompdf(12, .40, 7) = .1009

P(x=2) = binompdf(12, .35, 2) = .1088

P(x=3) = binompdf(12, .25, 3) = .2581

P( 7 will prefer candidate A & 2 will prefer candidate B & 3 will have no preference)

P = (1.009)(.1088)(.2581)