Question 853187: The numbers 1 through 10 are written in separate slips of paper, and the slips are placed into a box. Then, 4 of these slips are drawn at random. What is the probability that the drawn slips are "1", "2", "3", and "4", in that order?
I tried (10*10*10*10)/(4*4*4*4), but got the wrong answer and I'm really curious on how to solve this one.
Answer by richard1234(7193)   (Show Source):
You can put this solution on YOUR website! Umm, (10*10*10*10)/(4*4*4*4) is greater than 1. Check what you write to see if it makes sense first.
Hint: You need to draw a 1 first. What is the probability of picking 1? If you have already picked 1, what is the probability that you will draw 2, out of the nine remaining slips?
|
|
|
