SOLUTION: The diameter of an electric cable is normally distrubuted, with a mean of .9 inch and a standard deviation of 0.01 inch. What is the probability that the diameter will exceed 0.91

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Question 853084: The diameter of an electric cable is normally distrubuted, with a mean of .9 inch and a standard deviation of 0.01 inch. What is the probability that the diameter will exceed 0.91 inch? (you may need to use the standard normal distribution table. Round your answer to three decimal places.)
Any help would be appreciated.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

z = (.91-.9)/.01 = 1  NORMSDIST(1) = .8413

 p(X > .91) = 1 - .8413 = .1587