SOLUTION: How do you solve this equation exactly for x? 2^(x^2 - x) = 4

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Question 852999: How do you solve this equation exactly for x?
2^(x^2 - x) = 4
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

2^(x^2 - x) = 4

2^(x^2 - x) = 2^2

  x^2 - x = 2

 x^2 - x - 2 = 0

(x-2)(x+1) = 0,   x = 2   0r  x = -1