SOLUTION: A housewife paid for PHP 350 for a basket of oranges. She bought home 20% of the oranges and sold the remainder to her neighbors at PHP 5.50 each for a profit of PHP 105. How many

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: A housewife paid for PHP 350 for a basket of oranges. She bought home 20% of the oranges and sold the remainder to her neighbors at PHP 5.50 each for a profit of PHP 105. How many       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 8528: A housewife paid for PHP 350 for a basket of oranges. She bought home 20% of the oranges and sold the remainder to her neighbors at PHP 5.50 each for a profit of PHP 105. How many oranges did she buy?

Answer by prince_abubu(198) About Me  (Show Source):
You can put this solution on YOUR website!
Let's focus on the number of oranges in the basket. Since we don't know it, let's call it K. The problem says that she kept 20% for herself and sold the rest. If she kept 20%, there would have been 80% left to sell. That would be 0.80K oranges that she sold. They said that each of those oranges costed PhP 5.50 each, and she earned PhP 105 just by selling those oranges. So, 0.80K%2A5.50+=+105+ then would be the equation to solve.

0.80K%2A5.50+=+105+ <----- Start here.

0.80K%2A5.50+=+105+%2B+350+ <---- WHAT!!!?? What happened here? The problem said that she made a profit! She lost the PhP 350 first when she bought the basket. IF she made a profit of 105, that means that she should have regained the PhP 350 that she lost FIRST, and then gained the Php 105 after. That's why we add the PhP 350 she lost from buying.

4.4K+=+455+ <---- Simplified

K+=+103.4+ <----- There were about 103 or 104 oranges in that basket she bought.