SOLUTION: I am not sure if this is where I ask this question. The question asks, "Suppose that f(x)=x^2 and g(x)=3x+1. Find f(g(x)) and f(x-1). I have found f(g(x)). The answer would be (3x+
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-> SOLUTION: I am not sure if this is where I ask this question. The question asks, "Suppose that f(x)=x^2 and g(x)=3x+1. Find f(g(x)) and f(x-1). I have found f(g(x)). The answer would be (3x+
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Question 852776: I am not sure if this is where I ask this question. The question asks, "Suppose that f(x)=x^2 and g(x)=3x+1. Find f(g(x)) and f(x-1). I have found f(g(x)). The answer would be (3x+1)^2 and simplified it would be 9x^2+6x+2. I am having trouble setting up the f(x-1). Would that be (x^2-1)^2? I am confused. Thank you so much in advance for your help in this matter. Found 2 solutions by josgarithmetic, Alan3354:Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! I am not sure if this is where I ask this question. The question asks, "Suppose that f(x)=x^2 and g(x)=3x+1. Find f(g(x)) and f(x-1). I have found f(g(x)). The answer would be (3x+1)^2 and simplified it would be 9x^2+6x+2. I am having trouble setting up the f(x-1). Would that be (x^2-1)^2?
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f(x)=x^2
f(x-1) --> sub (x-1) for x
f(x-1) = (x-1)^2
f(x-1) = x^2 - 2x + 1