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Question 852728: Mighty Mouse(who flies at a constant speed of 1400 ft/sec) was standing next to a cannon that was pointed straight up. A cannonball was shot vertically into the air with an initial velocity of 880 ft/sec. Exactly one second after the cannon was fired, Mighty Mouse flew up to touch the bottom of the cannonball. He then immediately turned and flew back down to the touch the inside bottom of the cannon, then up to the cannonball, down into the cannon, and so on, until the cannonball fell back into the cannon's barrel.
A. What is total distance Mighty Mouse had flown when he was finally smashed by the cannonball into mouse-mush?
B. What was the total distance that the cannonball had flown?
C. When did Mighty Mouse first touch the cannonball and how high was it?
Answer by KMST(5328)   (Show Source):
You can put this solution on YOUR website! The cannonball accelerates downwards at   due to gravity.
At that rate it will go from 880 to 0 or from 0 to 880 ft/sec in  seconds.
It will go up and down in 55 seconds.
That is how long Mighty will survive after the cannon fires.
In that time, flying for 54 seconds at1400 ft/sec he will have covered
 feet.
At an average speed of 440 ft/sec, the cannonball covered
 feet in its 55-second flight.
 seconds after the cannon fires, the ball's height, in feet, will be
 and Mighty, flying straight up, can reach a height of
 feet by that time.
When Mighty first touches the ball we have
 .
Dividing everything by 8, we get
Solving we get  seconds.
That is 2.5 seconds from the cannon firing, and 1.5 seconds after Mighty takes off.
By then,
 feet.
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