SOLUTION: Kindly Solve this Problem Please.
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1. A person invested $ 15,000. The greater part is invested at 8% and smaller part at 6%. The a
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1. A person invested $ 15,000. The greater part is invested at 8% and smaller part at 6%. The a
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1. A person invested $ 15,000. The greater part is invested at 8% and smaller part at 6%. The annual income in the greater part is $ 200 more than the annual income of the smaller part. What is hte smaller part of the investment? Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website! .08*X=.06(15000-X)+200
.08X=900-.06X+200
.08X+.06X=1100
.14X=1100
X=1100/.14
X=7857.14 INVESTED @ 8%.
15000-7857.14=7142.86 INVESTED @ 6%.
PROOF
.08*7857.14=.06*7142.86+200
628.57=428.57+200
628.57=628.57
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