Question 852576: Hi, I couldn't figure out how to solve this problem. I tried 7! divided by 6! and the answer is 7, 6! cancels out the first 6 numbers of 7!. But the correct answer is 9. Please help.
Thanks a lot,
shayne
Mr. Lee bought 6 new pants and 7 new
shirts. Now he needs to buy new ties.
Mr. Lee wants to be able to wear a
different combination of one pant, one
shirt, and one tie every day for one
year. What is the minimum number of
ties he should buy?
Answer by richard1234(7193)   (Show Source):
You can put this solution on YOUR website! Why are you using 7!, 6! and dividing them? Ask yourself that first. The correct solution involves no factorials.
If Mr. Lee buys t ties, the number of pants-shirt-tie combinations is 6*7*t = 42t. We want 42t >= 365, and the smallest integer t such that the inequality is true is t = 9.
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