Question 852536: Find the foci this ellipse equation. Carefully graph the ellipse. Identify the coordinates of the four vertices on the graph. 4x^2+9y^2=36
Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website! ellipse
foci | ((-sqrt(5), 0) | (sqrt(5), 0))=((-2.23607, 0) | (2.23607, 0))
vertices | (-3, 0) | (3, 0)
center | (0, 0)
semimajor axis length | 3
semiminor axis length | 2
area | 6 pi=18.8496
perimeter | 12 E(5/9)=15.8654
focal parameter | 4/sqrt(5)=1.78885
eccentricity | sqrt(5)/3=0.745356
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