Question 852430: log2(x)+log2(x+1)=log2(6)
Answer by LinnW(1048)   (Show Source):
You can put this solution on YOUR website! log2(x)+log2(x+1)=log2(6)
log2(x)+log2(x+1) = log2(6)
log2(x*(x+1))) = log2(6)
log2(x*(x+1))) = log2(6)
log2(x^2 + x) = log2(6)
x^2 + x = 6
add -6 to each side
x^2 + x -6 = 0
(x + 3)(x - 2) = 0
x = -3 or x = 2
-3 does not work with the original equation, so x = 2
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