SOLUTION: The perimeter of a rectangle is 74m. If the width were doubled and the length increased by 10m, the perimeter would be 126m. What are the length and width of the rectangle?

Algebra ->  Rectangles -> SOLUTION: The perimeter of a rectangle is 74m. If the width were doubled and the length increased by 10m, the perimeter would be 126m. What are the length and width of the rectangle?      Log On


   

Question 852411: The perimeter of a rectangle is 74m. If the width were doubled and the length increased by 10m, the perimeter would be 126m. What are the length and width of the rectangle?
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
w width, y length
As started: 2w%2B2y=74
As changed: width is 2w, and length is y+10; so perimeter is 2%282w%29%2B2%28y%2B10%29=126

Simplifying the two equations, cutting through the steps, the system is:
-------------------
w+y=37
-
2w+y=53
-------------------

Elimination Method:
%282w%2By%29-%28w%2By%29=53-37
highlight%28w=16%29, .... highlight%28y=21%29.