SOLUTION: What is the solution of the proportion? n-6= n-5 3n 3n+1 I cross multiplied and got (n-6)(3n+1)=3n(n-5) and I then FOILed and did the distributive property and got 3n^2+n-18

Algebra ->  Proportions -> SOLUTION: What is the solution of the proportion? n-6= n-5 3n 3n+1 I cross multiplied and got (n-6)(3n+1)=3n(n-5) and I then FOILed and did the distributive property and got 3n^2+n-18      Log On


   

Question 852308: What is the solution of the proportion?
n-6= n-5
3n 3n+1
I cross multiplied and got (n-6)(3n+1)=3n(n-5) and I then FOILed and did the distributive property and got 3n^2+n-18n-6=3n^2-15n and I am now stuck and have no idea what to do next.. Please Help! Thank You ! :)
Answer by josh_jordan(263) About Me  (Show Source):
You can put this solution on YOUR website!
Hello, I'm unclear as to the actual proportion, but I'm assuming it's

%28n-6%29%2F3n=%28n-5%29%2F%283n%2B1%29

If this is the case, first, you need to cross-multiply, which you did, and you'd get:

(n - 6)(3n + 1) = 3n(n - 5) ----->

3n%5E2%2Bn-18n-6=3n%5E2-15n ----->

3n%5E2-17n-6=3n%5E2-15n

Next, get all of the n's and n^2's to one side, and the numbers to the other side. When you do this, you will get:

-2n=6

Now, you can solve for n, by dividing both sides of the equation by -2:

%28-2n%29%2F-2=6%2F-2 ----->

n=-3, which is your answer