SOLUTION: Find all solutions of each of the equations in the interval (0, 2pi) cos(x- pi/2) + sin^2x=0

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Question 852267: Find all solutions of each of the equations in the interval (0, 2pi)
cos(x- pi/2) + sin^2x=0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find all solutions of each of the equations in the interval (0, 2pi)
cos(x- pi/2) + sin^2x=0
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cos(x-π/2)=cosx*cos(π/2)+sinx*sin(π/2)=cosx*0+sinx*1=sinx
sinx+sin^2x=0
sinx(1+sinx)=0
sinx=0
x=π
or
sinx=-1
x=2π/3