SOLUTION: Martina leaves home at 9 am bicycling at a rate of 24mi/h. Two hours later, John leaves driving at the rate of 48mi/h. At what time will John catch up with Martina?
Algebra ->
Inequalities
-> SOLUTION: Martina leaves home at 9 am bicycling at a rate of 24mi/h. Two hours later, John leaves driving at the rate of 48mi/h. At what time will John catch up with Martina?
Log On
Question 85226: Martina leaves home at 9 am bicycling at a rate of 24mi/h. Two hours later, John leaves driving at the rate of 48mi/h. At what time will John catch up with Martina? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Martina leaves home at 9 am bicycling at a rate of 24mi/h. Two hours later, John leaves driving at the rate of 48mi/h. At what time will John catch up with Martina?
-------------
Martina DATA:
Rate = 24 mph ; Time = x hrs ; Distance = rt =24x miles
----------------
John DATA:
Rate = 48 mph ; Time = x-2 hrs; Distance = rt = 48(x-2) mi
-----------------
EQUATION:
distance = distance
24x = 48(x-2)
x=2x-4
x=4 hrs
------------
9 AM + 4 hrs = 1:00 PM
======================
Cheers,
Stan H.
(