Question 8522: What is the remainder of-
x^3+5x^2-6x+10(divided by) x+3
Answer by glabow(165)   (Show Source):
You can put this solution on YOUR website! This is a little hard to describe. You need to look up synthetic division to most easily solve this problem.
Basically, it is this: you divide x+3 into the polynomial.
x+3 divides (x^3+5x^2-6x+10) x^2 times. x^2 times x+3 is x^3+3x^2. You subtract this from the polynomial and you have 2x^2-6x+10 remaining.
x+3 divides into (2x^2-6x+10) 2x times. 2x times x+3 is 2x^2+6x. You subtract this from the polynomial you had left and you get -12x+10 remaining.
x+3 divides into (-12x+10) -12 times. -12 times x+3 is -12x-36. You subtract this from the polynomial you had left and you get 46 remaining.
You cannot divide x+3 into 46, so the remainder is 46/(x+3).
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