SOLUTION: {sqrt2x+4} = sqrt3x Not sure if my steps are wrong, or what; But, no matter what, I always get an answer that doesn't work as the outcome. What I did is below. Please help! Thanks

Algebra ->  Radicals -> SOLUTION: {sqrt2x+4} = sqrt3x Not sure if my steps are wrong, or what; But, no matter what, I always get an answer that doesn't work as the outcome. What I did is below. Please help! Thanks      Log On


   

Question 852133: {sqrt2x+4} = sqrt3x
Not sure if my steps are wrong, or what; But, no matter what, I always get an answer that doesn't work as the outcome. What I did is below. Please help! Thanks!
Here's what I did:
{sqrt2x+4} = sqrt3x
Square each side; ({sqrt2x+4})^2 = (sqrt3x)^2
Simplify; 2x + 4 = 3x
Subtract x from both sides (this is probably where I went wrong); x + 4 = 2x
Divide each side by 2; 2 = x

But, once plugging the solution into the problem, it does not fit.
Found 2 solutions by Fombitz, Alan3354:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The square of sqrt%282x%29%2B4 does not equal 2x%2B4.
Using the FOIL method,
%28sqrt%282x%29%2B4%29%28sqrt%282x%29%2B4%29=2x%2B4%2Asqrt%282x%29%2B4%2Asqrt%282x%29%2B16
%28sqrt%282x%29%2B4%29%5E2=2x%2B8%2Asqrt%282x%29%2B16
Continue from there and repost if you need more help.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%282x%2B4%29+=+sqrt%283x%29
2x + 4 = 3x
Subtract 2x
4 = x
x = 4