SOLUTION: binomial distribution
A quality inspector has drawn a sample of 16 light bulbs from a recent production line. Supposed 20% of the bulbs in the lot are defective. What is the pr
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A quality inspector has drawn a sample of 16 light bulbs from a recent production line. Supposed 20% of the bulbs in the lot are defective. What is the pr
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Question 852119: binomial distribution
A quality inspector has drawn a sample of 16 light bulbs from a recent production line. Supposed 20% of the bulbs in the lot are defective. What is the probability that exactly 6 bulbs from the sample are defective?
You can put this solution on YOUR website! We are going to use the General Binomial Probability formula
P(k out of n) = n!/(k!(n-k)!) * p^k * (1-p)^(n-k)
p = .20
k = 6
n = 16
P(6 out of 16) = 16! /(6!(16-6)!) * .2^6 * (1-.2)^(16-6)
P(6 out of 16) = 8008 * 6.4e-5 * 0.1073741824
P(6 out of 16) = 0.0550 = 0.06