Question 852011: You have a total of 23 nickels and dimes. The total amount you have is $1.95. How many of the coins are nickels and how many are dimes?
Answer by Seutip(231)   (Show Source):
You can put this solution on YOUR website! I really researched your currencies, I'm not familiar with it.
Since a dime is worth 10 cents or $.10
and a nickel is 5 cents or $.05
$1.95 is equal to 195 cents right?
So Let;
d - number of dimes
n - number of nickel
(1) d+n=23 this is our first equation
(2) 10d+5n=195 this is our second equation since the value of dime is 10 and nickel is 5
-------------------
Multiply both sides of (1) by 10 and subtract (1) from (2) (We use 10 in order to get rid of d)
-------------
(2) 10d+ 5n=195
(1) 10d+10n=230
Subtract (1) from (2)
(2) 10d+ 5n=195
(1)- 10d+10n=230
This is equal to
-5n=-35
n=7
Since n=7,
(1) d+n = 23
(1) d+7 = 23
It follows that,
(1) d=16
It means there are 7 nickels and 16 dimes!
Try to solve it if you get 195 in (2)
(2) 10d+5n=195 Substitute
(2) 10(16)+5(7)=195
(2) 160+35=195
Super okay!
Hope that helps!!
Follow me on twitter and instagram Pretty please?! @seutip
|
|
|
