SOLUTION: log3(x+3)=2+log3(x-1) [3's are the bases] I have: log3(x+3)-log3(x-1)=2 log3[(x+3)/(x-1)]=2 3^2=(x+3)/(x-1) 9x-9=x+3 8x=12 x=2/3 The answer is supposedly 1.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: log3(x+3)=2+log3(x-1) [3's are the bases] I have: log3(x+3)-log3(x-1)=2 log3[(x+3)/(x-1)]=2 3^2=(x+3)/(x-1) 9x-9=x+3 8x=12 x=2/3 The answer is supposedly 1.      Log On


   

Question 851947: log3(x+3)=2+log3(x-1) [3's are the bases]
I have:
log3(x+3)-log3(x-1)=2
log3[(x+3)/(x-1)]=2
3^2=(x+3)/(x-1)
9x-9=x+3
8x=12
x=2/3
The answer is supposedly 1.5, but I am getting 2/3.. help?

Answer by josh_jordan(263) About Me  (Show Source):
You can put this solution on YOUR website!
You were correct up until 8x = 12.

When you divide both sides of your equation by 8, you get

x = 12/8, which equals 3/2, not 2/3. 3/2 = 1.5 :)