Question 851888: could you help me find all the solutions in the interval [0, 2pi)
4sin^2(2x)-1=0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! could you help me find all the solutions in the interval [0, 2pi)
4sin^2(2x)-1=0
could you help me find all the solutions in the interval [0, 2pi)
sin^2(2x)=1/4
sin(2x)=±1/√2=±√2/2
2x=π/4, 3π/4, 5π/4, 7π/4
x=π/8, 3π/8, 5π/8, 7π/8
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