SOLUTION: Write the vertex form for a parabola with the given characteristics.
1. vertex ( 0, 0) directrix x = -15
2. vertex (3, 3) focus (3, 0)
3. Vertex ( 0, 0 ) focus ( 2, 0)
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-> SOLUTION: Write the vertex form for a parabola with the given characteristics.
1. vertex ( 0, 0) directrix x = -15
2. vertex (3, 3) focus (3, 0)
3. Vertex ( 0, 0 ) focus ( 2, 0)
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Question 851812: Write the vertex form for a parabola with the given characteristics.
1. vertex ( 0, 0) directrix x = -15
2. vertex (3, 3) focus (3, 0)
3. Vertex ( 0, 0 ) focus ( 2, 0)
Write the standard form for the parabola given the following equation.
4. x^2 + 8x - y + 20 = 0 Answer by ewatrrr(24785) (Show Source):
Hi,
sketch IT (Directrix x = 15 the clue) Parabola opening left a < 0
the vertex form of a Parabola opening right(a>0) or left(a<0),
where(h,k) is the vertex and y = k is the Line of Symmetry V(0,0) Finding value of a
p(distance of the directrix and focus left 0r right of vertex) = 15, a = 1/4p = -1/60 as a < 0
