SOLUTION: Find the value of cosx and sinx, given cosx=3/8 and secx<0

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Question 851696: Find the value of cosx and sinx, given cosx=3/8 and secx<0
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the value of cosx and sinx, given cosx = -3/8 and secx<0
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Note: If sec(x) < 0, cos(x) is also < 0
But sin(x) could be positive (QII) or negative(QIII).
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Since cos(x) = 3/8, sin(x) = sqrt(8^2-3^2)/8 = + or -sqrt(55)/8
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Cheers,
Stan H.
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