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Hi,
A fair die is rolled twice (36 outcomes)
P(sum between 3 and 7) = P(sum is 4, 5 0r 6) = 3/36 + 4/36 + 5/36 = 12/36 = 1/3
___1_2_3__4__5__6
1|_2_3_4__5__6__7
2|_3_4_5__6__7__8
3|_4_5_6__7__8__9
4|_5_6_7__8__9_10
5|_6_7_8__9_10_11
6|_7_8_9_10_11_12