SOLUTION: An apple costs the same as two oranges. Together an orange and a banana costs 10 cents more than an apple. Two oranges cost 15 cents more than a banana. What's the cost for each fr

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: An apple costs the same as two oranges. Together an orange and a banana costs 10 cents more than an apple. Two oranges cost 15 cents more than a banana. What's the cost for each fr      Log On


   

Question 851457: An apple costs the same as two oranges. Together an orange and a banana costs 10 cents more than an apple. Two oranges cost 15 cents more than a banana. What's the cost for each fruit?"
Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
Here's what we know:
A = 2R
R + B = 10 + A
2R = B + 15
.
Since A = 2R and 2R = B + 15, A = B + 15
Let's take that value of A and plug it into the second equation.
R + B = 10 + B + 15
R + B = B + 25
Subtract B from each side
R = 25
.
If oranges are .25, then apples are .50 each (An apple costs the same as two oranges.)
If 2 oranges cost .50 and a banana is .50 less than that, a banana is .35.
.
Let's see if it works for the other equation: Together an orange and a banana costs 10 cents more than an apple.
.25 + .35 = .10 + .50
.60 = .60
Success!