Hi,
m = 120, SD = 8
Since this is a continuous function, we have P(x > 122) = P(x ≥ 122).
using TI
P(x ≥ 122) = normalcdf(smaller, larger, µ, σ) = normalcdf(122, 9999, 120, 8)
Note: The 9999 is used as the larger value to be least 5 standard deviations from the mean.
Or using z value
z = 2/8 = .25 NORMSDIST(0.25) = .5987
P(x ≥ 122) = 1 - .5987