SOLUTION: Given three consecutive integers with a sum of four times the second number, write an algebraic equation for this situation. A) n+n+1+n+2=(n+1) B) n+n+1+n+2=4n C) 3n+3=4n+4

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Given three consecutive integers with a sum of four times the second number, write an algebraic equation for this situation. A) n+n+1+n+2=(n+1) B) n+n+1+n+2=4n C) 3n+3=4n+4       Log On


   

Question 851190: Given three consecutive integers with a sum of four times the second number, write an algebraic equation for this situation.
A) n+n+1+n+2=(n+1)
B) n+n+1+n+2=4n
C) 3n+3=4n+4
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive integers: n, (n+1), (n+2)

n + (n+1) + (n+2) = 4(n+1)
3n + 3 = 4n + 4

C) is correct.