SOLUTION: find three consecutive positive integers such that the square of the first plus the square of the third is 100

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Question 851096: find three consecutive positive integers such that the square of the first plus the square of the third is 100
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
n, n+1, n+2; the three consecutive positive integers.
n%5E2%2B%28n%2B2%29%5E2=100 is the described requirement.

Algebraic steps:
n%5E2%2Bn%5E2%2B4x%2B4=100
2n%5E2%2B4x-96=0
n%5E2%2B2x-48=0
%28n-6%29%28n%2B8%29=0 and you must use only the positive solution of n.
highlight%28n=6%29

The numbers are 6, 7, 8.