SOLUTION: The hypotenuse of a right triangle is 75 inches long. One leg is 5 inch(es) longer than the other. Find the lengths of the legs of the triangle. Round your answers to the nearest t
Algebra ->
Triangles
-> SOLUTION: The hypotenuse of a right triangle is 75 inches long. One leg is 5 inch(es) longer than the other. Find the lengths of the legs of the triangle. Round your answers to the nearest t
Log On
Question 851082: The hypotenuse of a right triangle is 75 inches long. One leg is 5 inch(es) longer than the other. Find the lengths of the legs of the triangle. Round your answers to the nearest tenth of an inch. Answer by ramkikk66(644) (Show Source):
The hypotenuse of a right triangle is 75 inches long. One leg is 5 inch(es) longer than the other. Find the lengths of the legs of the triangle. Round your answers to the nearest tenth of an inch.
Solution:
Let the shortest side be x
Then the second side is x + 5
And the hypotenuse is 75 in. long.
Applying Pythagoras theorem,
i.e. or Dividing it by 2 throughout
This can be solved using the quadratic solver as shown below.
Quadratic equation (in our case ) has the following solutons:
For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=11225 is greater than zero. That means that there are two solutions: .
Quadratic expression can be factored:
Again, the answer is: 50.4740502510427, -55.4740502510427.
Here's your graph:
The solution is the positive value of x is 50.5 inches (rounded off), since the length of a side cannot be negative.
So the lengths of the sides are , , and inches respectively.
:)