SOLUTION: A bacteria culture started with a count of 480 at 8:00 A.M. and after t hours is expected to grow to f(f)=480(c/2)^t. Estimate the number of bacteria in the culture at noon the sa

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: A bacteria culture started with a count of 480 at 8:00 A.M. and after t hours is expected to grow to f(f)=480(c/2)^t. Estimate the number of bacteria in the culture at noon the sa      Log On


   



Question 85089: A bacteria culture started with a count of 480 at 8:00 A.M. and after t hours is expected to grow to f(f)=480(c/2)^t. Estimate the number of bacteria in the culture at noon the same day.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A bacteria culture started with a count of 480 at 8:00 A.M. and after t hours is expected to grow to f(t)=480(1/2)^t. Estimate the number of bacteria in the culture at noon the same day.
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I assumed your posted "c/2" was really "1/2"
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From 8:00 to noon is 4 hours.
f(4) = 480(1/2)^4 = 480/16 = 30 bacteria
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Cheers,
Stan H.