SOLUTION: a and b are quadrant I angles wieth cos (a) 15/17 and csc(b)=41/9. find tan(a+b)
A 455/528 B 37/120 c 91/120 d. 185/672
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-> SOLUTION: a and b are quadrant I angles wieth cos (a) 15/17 and csc(b)=41/9. find tan(a+b)
A 455/528 B 37/120 c 91/120 d. 185/672
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Question 850532: a and b are quadrant I angles wieth cos (a) 15/17 and csc(b)=41/9. find tan(a+b)
A 455/528 B 37/120 c 91/120 d. 185/672 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a and b are quadrant I angles with
cos (a) 15/17)
sin(a) = sqrt(17^2-15^2)/17 = 8/17
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and csc(b)=41/9
sin(b) = 9/41
cos(b = = sqrt(41^2-9^2)/41 = 40/41
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find tan(a+b) = [tan(a)+tan(b)]/[1-tan(a)tan(b)]
= [(8/15)+(9/40)]/[1-(8/15)(9/40)] = 455/528
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Cheers,
Stan H.
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A 455/528 B 37/120 c 91/120 d. 185/672
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