SOLUTION:
A chemist mixed 3 liters of 30% sulfuric acid with a sample of 80% sulfuric acid to obtain a sample of 60% sulfuric acid. How much of the 80% sulfuric acid was used?
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A chemist mixed 3 liters of 30% sulfuric acid with a sample of 80% sulfuric acid to obtain a sample of 60% sulfuric acid. How much of the 80% sulfuric acid was used?
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Question 850346:
A chemist mixed 3 liters of 30% sulfuric acid with a sample of 80% sulfuric acid to obtain a sample of 60% sulfuric acid. How much of the 80% sulfuric acid was used? Answer by checkley79(3341) (Show Source):
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.80X+.30*3=.60(X+3)
.80X+.9=.60X+1.8
.80X-.60X=1.8-.9
.20X=.9
X=.9/.20
X=4.5 LITERS OF THE 80% WERE USED.
PROOF:
.80*4.5+.30*3=.60(4.5+3)
3.6+.9=.60*7.5
4.5=4.5
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