SOLUTION: I need help solving this word problem. A chemist mixed 3 liters of 30% sulfuric acid with a sample of 80% sulfuric acid to obtain a sample of 60% sulfuric acid. How much of the

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Question 850342: I need help solving this word problem.
A chemist mixed 3 liters of 30% sulfuric acid with a sample of 80% sulfuric acid to obtain a sample of 60% sulfuric acid. How much of the sulfuric acid was used?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = liters of the 80% solution needed
+.8x+ = liters of sulfuric acid in 80% solution
+.3%2A3+=+.9+ liters of sulfuric acid in 30% solution
----------------------------------------------------------
+%28+.9+%2B+.8x+%29+%2F+%28+3+%2B+x+%29+=+.6+
+.9+%2B+.8x+=+.6%2A%28+3+%2B+x+%29+
+.9+%2B+.8x+=+1.8+%2B+.6x+
+.2x+=+.9+
+x+=+4.5+
4.5 liters of the 80% solution are needed
check:
+%28+.9+%2B+.8x+%29+%2F+%28+3+%2B+x+%29+=+.6+
+%28+.9+%2B+.8%2A4.5+%29+%2F+%28+3+%2B+4.5+%29+=+.6+
+%28+.9+%2B+3.6+%29+%2F+7.5+=+.6+
+4.5+=+.6%2A7.5+
+4.5+=+4.5+
OK
The problem is poorly stated. I'm not sure this is
what they want, but you can figure out anything about
the problem using what's here. Hope this helps