SOLUTION: Two cars leave a a city on the same road, one driving 12mph faster than the other. After 4 hours, the car traveling faster stops for lunch. After 4 and a half hours, the car travel
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Question 850199: Two cars leave a a city on the same road, one driving 12mph faster than the other. After 4 hours, the car traveling faster stops for lunch. After 4 and a half hours, the car traveling slower stops for lunch. Assuming that the person in the faster car is still eating lunch, the cars are now 24 miles apart. How fast is each car driving? Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! 4*(12+x)-24=4.5x
x=48 mph for the slower car
12+x=60 mph faster car
4*60=240
4.5*48=216 which is 24 miles from faster car
