SOLUTION: There are 3 times as many pears as oranges. A group of children receive 5 oranges abd 8 pears each. All the oranges are given away, but there are 21 pears left. How many children a

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: There are 3 times as many pears as oranges. A group of children receive 5 oranges abd 8 pears each. All the oranges are given away, but there are 21 pears left. How many children a      Log On


   



Question 849855: There are 3 times as many pears as oranges. A group of children receive 5 oranges abd 8 pears each. All the oranges are given away, but there are 21 pears left. How many children are there, and how many oranges are there?
Answer by AnlytcPhil(1807) About Me  (Show Source):
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There are 3 times as many pears as oranges. A group of children receive 5 oranges and 8 pears each. All the oranges are given away, but there are 21 pears left. How many children are there, and how many oranges are there?
Im sorry ..let me rephrase ..how do i write the equation? Like, let x be number of children and y the number of oranges ..how do you do the equation if its like that ? 'Cause in my homework it saya it should be like that ..

Let x be number of children and y the number of oranges. 

All the oranges are given away and each child has 5 oranges.

So the number of oranges is 5 times the number of children.  So
one equation is

                          y = 5x

Since there are 3 times as many pears as oranges,

the number of pears is 3 times the number of oranges, so

the number of pears = 3y

Since there were 21 pears left, 

there were only 3y-21 pears received, because we subtract the 21
from the number of pears to get the number of pears given out.

Since each child received 8 pears,

The number of pears received = 8 times the number of children.

                      3y-21 = 8x
                          
So we have this system of equations:

                          y = 5x
                      3y-21 = 8x

We use the method of substitution.  We substitute 5x
for y in the second equation.

                   3(5x)-21 = 8x
                     15x-21 = 8x   

Add +21 to both sides 

                     15x-21 = 8x                   
                        +21     +21
                    -----------------
                     15x    = 8x+21

Add -8x to both sides of the equation:

                      15x    = 8x+21
                      -8x     -8x
                    -----------------
                       7x    =    21
                     
Divide both sides by 7

                        x    =    3

Substitute x=3 into        y = 5x      
                           y = 5(3) = 15

So there were x=3 children and y=15 oranges 


That's all you were asked for but we must find the number of
pairs so we can check the problem.

Since the number of pears = 3y, 3(15) = 45

So there were 45 pears. 

Now we check the sentences in the problem, with

3 children, 15 oranges, and 45 pears.
There are 3 times as many pears as oranges. 

That checks because 3×15 = 45

A group of children receive 5 oranges...All the oranges are given away,
The oranges check because 5×3 = 15 

...and 8 pears each...but there are 21 pears left.
8×3 = 24 pears given out plus the 21 left over is 24+21=45
So that checks.

So 3 children, 15 oranges, and 45 pears is correct.     

Edwin