SOLUTION: solve for x: 1) 2log(2x+8)=4 2) logx-log4=-2 3) e^ln5x=20 4) e^x+6 + 5=1 5) ln(x-3)=2 6) log base5 (3x+20)- 3log base5 2=2

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: solve for x: 1) 2log(2x+8)=4 2) logx-log4=-2 3) e^ln5x=20 4) e^x+6 + 5=1 5) ln(x-3)=2 6) log base5 (3x+20)- 3log base5 2=2      Log On


   

Question 849543: solve for x:
1) 2log(2x+8)=4
2) logx-log4=-2
3) e^ln5x=20
4) e^x+6 + 5=1
5) ln(x-3)=2
6) log base5 (3x+20)- 3log base5 2=2
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

1) 2log(2x+8)=4  10%5E2+=+2x%2B8

2) logx-log4= log(x/4) = -2   1%2F10%5E2+=+x%2F4

3) e^ln5x=20  5x+=+20

4) e^x+6 = -4  |Cannot take ln of both sides of EQ to solve;  NO Solution

5) ln(x-3)=2  e%5E2+=+x-3

6) log base5 (3x+20)- 3log base5 2 = log%285%2C%283x%2B20%29%2F8%29%29+ =2  5%5E2+=+%283x%2B20%29%2F8%29%29















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+e%5E%28lnx%29+=+x

log%28a%2C+p%29+=+log%28b%2Cp%29%2F+%28log%28b%2C+a%29%29+