The equation of the line that passes through the
points (-2,6) and (4,-3) is what?
First we find the slope by using the slope formula:
m =
where (x1,y1) = (-2,6)
and where (x2,y2) = (4,-3)
m =
m =
m =
m =
Then we use the
point-slope formula:
y - y1 = m(x - x1)
where (x1,y1) = (-2,6)
y - 6 =
[x - (-2)]
y - 6 =
(x + 2)
y - 6 =
x - 3
y =
x + 3
Edwin