SOLUTION: the area of a rectangle is 21yd squared and the length of the rectangle is 1yd less than the width. find the dementions of the rectangle

Algebra ->  Rectangles -> SOLUTION: the area of a rectangle is 21yd squared and the length of the rectangle is 1yd less than the width. find the dementions of the rectangle      Log On

 

Hi,



Let x represent  the width

(x-1yd)x = 21yd^2

 x^2 -x -21 = 0   (Tossing out the negative solution for unit measure)

, the width

, the length